A-1
ALGEBRA 2 Β· Quadratic Formula
x = 3 and x = 1/2
a=2,b=β7,c=3 β D = 49β24 = 25 β x = (7Β±5)/4
A-2
ALGEBRA 2 Β· Discriminant
No real solutions (D < 0)
D = 4 β 60 = β56 < 0 β 2 complex/imaginary solutions
A-3
ALGEBRA 2 Β· Factoring
(x + 3)(x + 4) = 0 β x = β3, x = β4
Need p+q=7 and pΓq=12 β 3 and 4 β
A-4
ALGEBRA 2 Β· Vertex Form
Vertex (β2, 7), opens DOWNWARD (a = β1 < 0)
y = β(x+2)Β²+7 β h = β2, k = 7, a = β1
A-5
ALGEBRA 2 Β· Exponential
y = 20000Β·(0.85)Λ£ β After 3 years β $12,282
Decay: b = 1 β 0.15 = 0.85 Β· 20000 Γ 0.85Β³ β 12,282
A-6
ALGEBRA 2 Β· Logarithms
(a) 4 Β· (b) β2
(a) 3β΄=81 β logβ(81)=4 Β· (b) 5β»Β²=1/25 β logβ
(1/25)=β2
A-7
ALGEBRA 2 Β· Absolute Value
x β€ β4 OR x β₯ 3
|2x+1| β₯ 7 β 2x+1 β₯ 7 or 2x+1 β€ β7 β x β₯ 3 or x β€ β4
A-8
ALGEBRA 2 Β· Remainder Theorem
Remainder = β4
x+1 β plug in x=β1: 2(β1)Β³+(β1)Β²β5 = β2+1β5 = β6... wait: = β6. Check: 2(β1)=β2, (β1)Β²=1 β β2+1β5=β6
A-9
ALGEBRA 2 Β· Rational Functions
V.A.: x = β3, Hole at x = 2
xΒ²+xβ6=(x+3)(xβ2) Β· (xβ1) doesn't cancel Β· bottom factors: (x+3)(xβ2)=0 Β· xβ1 β factor of bottom β check again: hole where top=bottom factor. Here no cancellation β V.A. at x=2 and x=β3
A-10
ALGEBRA 2 Β· Nonlinear Systems
(3, 5) and (β1, β3)
xΒ²β4=2xβ1 β xΒ²β2xβ3=0 β (xβ3)(x+1)=0 β x=3,β1
G-1
GEOMETRY Β· Angles
Other angle = 65Β°
Exterior 120Β° = sum of 2 non-adjacent β 120 β 55 = 65Β°
G-2
GEOMETRY Β· Pythagorean
(a) 13 Β· (b) 15
(a) 25+144=169=13Β² Β· (b) 289β64=225=15Β²
G-3
GEOMETRY Β· Special Triangles
45-45-90: legs = 6β2 Β· 30-60-90: short=7, long=7β3
45-45-90: hyp=xβ2=12 β x=12/β2=6β2 Β· 30-60-90: hyp=2x=14 β x=7
G-4
GEOMETRY Β· Circles
A=25Ο Β· C=10Ο Β· Arc=10Ο/3
r=5 (d=10 β r=5) Β· A=Ο(25)=25Ο Β· Arc=(120/360)Β·10Ο=10Ο/3
G-5
GEOMETRY Β· Parallel Lines
x = 30
Co-interior: (3x+15)+(x+45)=180 β 4x+60=180 β 4x=120 β x=30
G-6
GEOMETRY Β· Similar Triangles
YZ = 9
10/6 = 15/YZ β 10Β·YZ = 90 β YZ = 9
G-7
GEOMETRY Β· Volume
Sphere: 288Ο Β· Cone: 48Ο
Sphere: (4/3)Ο(216)=288Ο Β· Cone: (1/3)Ο(16)(9)=48Ο
G-8
GEOMETRY Β· Coordinate
Midpoint (1, 4) Β· Distance = 10
M=((β3+5)/2,(1+7)/2)=(1,4) Β· D=β(64+36)=β100=10
G-9
GEOMETRY Β· Polygons
Each interior = 135Β° Β· Each exterior = 45Β°
n=8: (8β2)Γ180=1080 Γ· 8 = 135Β° Β· Exterior: 360Γ·8=45Β°
G-10
GEOMETRY Β· Congruence
(a) SSS β Β· (b) ASA β Β· (c) NOT congruent (AAA = similar only)
AAA proves SIMILARITY not congruence β the triangles could be different sizes!