SAT Math ยท Self-Study Workbook
Geometry
Master Notes
10 Core Topics ยท 10 Key Problems
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Date started: ___________________________
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Vertical angles are EQUAL. Supplementary angles add up to 180ยฐ. Complementary angles add up to 90ยฐ.
๐ KEY WORDS: Vertical = Equal / Supplement = 180 / Complement = 90
Two lines intersect. One angle is 3x + 10. Its vertical angle is 5x โ 20. Find x.
๐ก Vertical angles are equal!
\(3x + 10 = 5x - 20\)
\(30 = 2x\)
\(x = 15\)
(A) 20
(B) 25
(C) 26.67
(D) 30
My Work & Answer
๐ชค TRAP: Don't set them equal โ they're supplementary!
The three angles of ANY triangle always sum to 180ยฐ. An exterior angle equals the sum of the two non-adjacent interior angles.
๐ KEY WORDS: Interior Sum = 180 / Exterior = Remote Interior ร 2
A triangle has angles \(x\), \(2x\), and \(3x\). Find each angle.
\(x + 2x + 3x = 180\)
\(6x = 180 \Rightarrow x = 30\)
Angles: 30ยฐ, 60ยฐ, 90ยฐ โ it's a right triangle!
(A) 110ยฐ
(B) 120ยฐ
(C) 130ยฐ
(D) 140ยฐ
My Work & Answer
๐ชค TRAP: Exterior angle = 180ยฐ โ interior angle at C (not 180ยฐ โ 90ยฐ)
In a right triangle: \(a^2 + b^2 = c^2\) where c is the hypotenuse (longest side, opposite the right angle).
๐ MEMORIZE TRIPLES: 3-4-5 / 5-12-13 / 8-15-17 / 7-24-25
A right triangle has legs 6 and 8. Find the hypotenuse.
\(6^2 + 8^2 = c^2\)
\(36 + 64 = 100\)
\(c = \sqrt{100} = 10\) โ (Recognize: 6-8-10 is a 3-4-5 triple ร 2!)
(A) 11
(B) 13
(C) 14
(D) 17
My Work & Answer
๐ชค TRAP: 5 + 12 = 17 is WRONG. You need \(\sqrt{5^2+12^2}\)
45-45-90: sides in ratio 1 : 1 : โ2 30-60-90: sides in ratio 1 : โ3 : 2
๐ 45-45-90 โ multiply leg ร โ2 to get hypotenuse
๐ 30-60-90 โ short leg ร 2 = hypotenuse; short leg ร โ3 = long leg
(A) \(5\)
(B) \(5\sqrt{2}\)
(C) \(5\sqrt{3}\)
(D) \(10\sqrt{3}\)
My Work & Answer
๐ชค TRAP: hyp = 2x โ x = 5. Long leg = 5โ3, NOT 5โ2!
Central angle = Arc measure. Inscribed angle = ยฝ ร Arc measure. Arc length = \(\dfrac{\theta}{360} \times 2\pi r\). Sector area = \(\dfrac{\theta}{360} \times \pi r^2\).
๐ INSCRIBED ANGLE = HALF the intercepted arc
๐ Arc Length โ think "fraction of circumference"
๐ Sector Area โ think "fraction of total area"
A circle has radius 6. A sector has a central angle of 90ยฐ. Find its area.
\(\text{Sector Area} = \dfrac{90}{360} \times \pi(6)^2 = \dfrac{1}{4} \times 36\pi = 9\pi\)
(A) 55ยฐ
(B) 65ยฐ
(C) 70ยฐ
(D) 110ยฐ
My Work & Answer
๐ชค TRAP: Inscribed = 110/2 = 55ยฐ. Central = 110ยฐ. Difference = 55ยฐ.
Triangle area: \(\dfrac{1}{2}bh\) ยท Trapezoid: \(\dfrac{1}{2}(b_1+b_2)h\) ยท Regular polygon: use apothem!
๐ TRAP(ezoid) has TWO bases โ average them, then ร height
๐ "Height" is ALWAYS perpendicular to the base
(A) 24
(B) 33
(C) 42
(D) 48
My Work & Answer
๐ชค TRAP: Trapezoid = ยฝ(8+14)ร6 = 66. Triangle = ยฝร14ร6 = 42. Diff = 24!
If two triangles are similar (AA, SAS, SSS), corresponding sides are proportional. If the sides ratio is \(k\), then areas ratio is \(k^2\)!
๐ SIDES ratio = k โ AREA ratio = kยฒ โ VOLUME ratio = kยณ
๐ AA (Angle-Angle) is the easiest similarity proof
Two similar triangles have corresponding sides 4 and 6. The area of the smaller triangle is 20. Find the larger triangle's area.
Ratio of sides: \(\dfrac{6}{4} = \dfrac{3}{2}\)
Ratio of areas: \(\left(\dfrac{3}{2}\right)^2 = \dfrac{9}{4}\)
Larger area: \(20 \times \dfrac{9}{4} = 45\)
(A) 30
(B) 36
(C) 40
(D) 45
My Work & Answer
๐ชค TRAP: Scale = 15/5 = 3. Small perimeter = 12. Large = 12 ร 3 = 36!
Cylinder: \(V = \pi r^2 h\). Cone: \(V = \dfrac{1}{3}\pi r^2 h\). Sphere: \(V = \dfrac{4}{3}\pi r^3\). SA of sphere: \(4\pi r^2\).
๐ Cone/Pyramid = โ
ร (base shape) ร height
๐ "Surface Area" = SUM of all faces
๐ SPHERE: "4 great circles" โ SA = 4ฯrยฒ
(A) \(\dfrac{1}{4}\)
(B) \(\dfrac{1}{3}\)
(C) \(\dfrac{1}{2}\)
(D) \(\dfrac{2}{3}\)
My Work & Answer
๐ชค TRAP: Cone = โ
ร Cylinder ALWAYS. Ratio = 1:3 โ cone/cylinder = 1/3
Midpoint: \(\left(\dfrac{x_1+x_2}{2},\, \dfrac{y_1+y_2}{2}\right)\). Distance: \(\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\). Slope: \(\dfrac{y_2-y_1}{x_2-x_1}\).
๐ MIDPOINT = average the coordinates
๐ DISTANCE = diagonal of a right triangle โ Pythagorean theorem!
๐ Perpendicular slopes โ product = โ1 (negative reciprocal)
(A) \((3.5,\,-1)\)
(B) \((7,\, 4)\)
(C) \((8,\, 5)\)
(D) \((10,\, 2)\)
My Work & Answer
๐ชค TRAP: B = 2M โ A โ x: 2(5)โ2=8, y: 2(1)โ(โ3)=5 โ B=(8,5)
Standard form of a circle: \((x-h)^2 + (y-k)^2 = r^2\) where (h, k) is the center and r is the radius.
๐ CENTER: read (h, k) directly โ but WATCH THE SIGNS!
๐ RADIUS: take โ of the right side
๐ Must COMPLETE THE SQUARE if given general form axยฒ+bx+...
What is the center and radius of \((x-3)^2 + (y+4)^2 = 25\)?
Center: \((3,\,-4)\) โ Watch! \(y+4\) means \(k = -4\)
Radius: \(r = \sqrt{25} = 5\)
(A) 3
(B) 4
(C) 5
(D) \(\sqrt{34}\)
My Work & Answer
๐ชค TRAP: Complete the square โ (xโ3)ยฒ+(y+4)ยฒ=16 โ r=4, not rยฒ=4!
๐ง The #1 Most Common Mistake: Confusing "radius" and "diameter." Always double-check: does the problem give you r or d? If d, divide by 2 first!
๐ DIAMETER = 2 ร RADIUS. Always. Every time.
~ Keep going. You've got this! ๐ช ~
SAT GEOMETRY NOTES ยท 10 TOPICS ยท 10 PROBLEMS