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πŸ““ My Study Notes
Pre-Calculus
Self-Study Pack
20 Core Questions Β· Vectors Β· Matrices Β· Polar Β· Trig
🎯 Vectors πŸ“Š Matrices πŸŒ€ Polar γ€° Trig
β˜… Click an answer β†’ correct: πŸŽ‰ confetti!  |  wrong: πŸ“– explanation shown
β˜… Each question has a memory keyword to help you explain it in English!

πŸ“‹ Table of Contents
β‘  Vectors (Q1–Q5)Magnitude Β· Direction Β· Dot Product
β‘‘ Matrices (Q6–Q9)Operations Β· Determinant Β· Inverse
β‘’ Polar Graphs (Q10–Q13)Coordinates Β· Equations Β· Conversion
β‘£ Trigonometry (Q14–Q18)Unit Circle Β· Laws Β· Identities
β‘€ Mixed Challenge (Q19–Q20)Cross-topic Connections
🎯 Section 1 · Vectors
MIND Β· Magnitude  |  Inverse (negative)  |  Not scalar  |  Direction matters
β†’ A vector has BOTH size AND direction. A scalar has only size.
πŸ“˜ Quick Example
If \(\vec{a} = \langle 3, 4 \rangle\), then \(|\vec{a}| = \sqrt{3^2+4^2} = \sqrt{25} = 5\)
← Use the Pythagorean theorem! The magnitude IS the hypotenuse.
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🎯 VECTORS · Magnitude
β˜… Easy β€” but students write the formula wrong!
Find the magnitude of vector \(\vec{v} = \langle -5,\; 12 \rangle\).
⚠️ Tricky: negative components don't make magnitude negative!
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🎯 VECTORS · Direction Angle
β˜… Easy β€” but many students forget which quadrant!
Vector \(\vec{u} = \langle -4,\; 4 \rangle\). What is the direction angle \(\theta\) (measured from positive x-axis)?
⚠️ \(\tan^{-1}\) alone won't give the right quadrant β€” check signs!
\(\vec{a} \cdot \vec{b} = |\vec{a}||\vec{b}|\cos\theta \quad\Longleftrightarrow\quad \cos\theta = \dfrac{a_1 b_1 + a_2 b_2}{|\vec{a}||\vec{b}|}\)
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🎯 VECTORS · Dot Product & Perpendicularity
β˜…β˜… Medium β€” most missed question on tests!
\(\vec{p} = \langle 3,\; k \rangle\) and \(\vec{q} = \langle 4,\; -6 \rangle\). If \(\vec{p} \perp \vec{q}\), find \(k\).
πŸ’‘ Perpendicular means dot product = 0. Always!
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🎯 VECTORS · Vector Addition & Scalar Multiplication
β˜… Easy β€” but students mix up order!
Given \(\vec{a} = \langle 2,\; -1 \rangle\) and \(\vec{b} = \langle -3,\; 4 \rangle\), calculate \(2\vec{a} - 3\vec{b}\).
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🎯 VECTORS · Unit Vector
β˜…β˜… Medium β€” formula correct but arithmetic slips!
Find the unit vector in the direction of \(\vec{w} = \langle 6,\; 8 \rangle\).
πŸ’‘ UNIT = divide every component by the magnitude. Result always has magnitude 1.
πŸ“Š Section 2 Β· Matrices
RIDE Β· Row times column  |  Inverse: flip & divide  |  Determinant: adβˆ’bc  |  Equal dimensions to add
β†’ Matrix multiplication: (mΓ—n)(nΓ—p) = (mΓ—p) β€” middle must match!
πŸ”‘ For 2Γ—2:   \(\det\begin{pmatrix}a&b\\c&d\end{pmatrix} = ad - bc\)    \(A^{-1} = \dfrac{1}{ad-bc}\begin{pmatrix}d&-b\\-c&a\end{pmatrix}\)
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πŸ“Š MATRICES Β· Multiplication
β˜…β˜… Medium β€” Row Γ— Column, not element-wise!
Compute \(AB\) where \(A = \begin{pmatrix}1&2\\3&4\end{pmatrix}\) and \(B = \begin{pmatrix}5&0\\1&-1\end{pmatrix}\).
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πŸ“Š MATRICES Β· Determinant
β˜… Easy β€” adβˆ’bc, but students switch b and c!
Find \(\det(M)\) for \(M = \begin{pmatrix}4&-3\\2&5\end{pmatrix}\).
⚠️ det = 0 means the matrix has NO inverse!
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πŸ“Š MATRICES Β· Inverse Matrix
β˜…β˜… Medium β€” swap a&d, negate b&c, then divide by det
Find \(A^{-1}\) for \(A = \begin{pmatrix}3&1\\5&2\end{pmatrix}\).
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πŸ“Š MATRICES Β· Solving System with Matrices
β˜…β˜… Medium β€” set up matrix equation first!
Use the matrix equation \(AX = B\) to solve: \(\begin{cases} 2x + y = 7 \\ x + 3y = 11 \end{cases}\)
πŸ’‘ \(X = A^{-1}B\) Β· First find \(\det(A)\)!
πŸŒ€ Section 3 Β· Polar Graphs
CART Β· Convert with cos/sin  |  Angle is ΞΈ from x-axis  |  Radius is r (can be negative!)  |  Two names for one point
β†’ \(x = r\cos\theta,\quad y = r\sin\theta,\quad r^2 = x^2+y^2\)
πŸ“˜ Conversion Cheat
Polar \((r,\theta)\) β†’ Rectangular: \(\;x=r\cos\theta,\; y=r\sin\theta\)
Rectangular \((x,y)\) β†’ Polar: \(\;r=\sqrt{x^2+y^2},\; \theta=\tan^{-1}\!\left(\tfrac{y}{x}\right)\) (adjust quadrant!)
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πŸŒ€ POLAR Β· Coordinate Conversion
β˜… Easy β€” plug into formulas carefully
Convert polar point \(\left(4,\; \dfrac{\pi}{3}\right)\) to rectangular \((x, y)\).
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πŸŒ€ POLAR Β· Rectangular β†’ Polar
β˜…β˜… Medium β€” always check the quadrant for ΞΈ!
Convert \((-3,\; 3)\) to polar form \((r,\theta)\) with \(r > 0\) and \(0 \le \theta < 2\pi\).
⚠️ x is negative, y is positive β†’ Quadrant II!
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πŸŒ€ POLAR Β· Graph Identification
β˜…β˜… Medium β€” tricky shape names!
The polar equation \(r = 3 + 3\cos\theta\) traces which shape?
πŸ’‘ If \(a = b\) in \(r = a + b\cos\theta\), the curve passes through the pole (origin).
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πŸŒ€ POLAR Β· Negative r Value
β˜…β˜…β˜… Hard concept β€” many students skip this!
The polar point \(\left(-2,\; \dfrac{\pi}{6}\right)\) is identical to which of the following?
⚠️ Negative r means: go in the opposite direction. Add Ο€ to the angle!
γ€° Section 4 Β· Trigonometry
ASTC Β· All (Q1)  |  Sin (Q2)  |  Tan (Q3)  |  Cos (Q4) β€” which trig ratio is positive per quadrant
Mnemonic: "All Students Take Calculus" πŸ“
\(\sin^2\theta + \cos^2\theta = 1 \qquad \tan\theta = \dfrac{\sin\theta}{\cos\theta} \qquad 1 + \tan^2\theta = \sec^2\theta\)
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γ€° TRIG Β· Unit Circle Values
β˜… Easy β€” but students confuse sin and cos positions!
Evaluate exactly: \(\sin\!\left(\dfrac{5\pi}{6}\right)\)
πŸ’‘ Reference angle of \(\tfrac{5\pi}{6}\) is \(\tfrac{\pi}{6}\). Quadrant II β†’ sin is positive!
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γ€° TRIG Β· Pythagorean Identity
β˜…β˜… Medium β€” use identity, don't find the angle!
If \(\cos\theta = -\dfrac{3}{5}\) and \(\theta\) is in Quadrant III, find \(\sin\theta\).
⚠️ In Q3: sin is also negative!
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γ€° TRIG Β· Law of Sines
β˜…β˜… Medium β€” set up the ratio correctly!
In triangle \(ABC\), \(A = 30Β°\), \(B = 45Β°\), and \(a = 6\). Find side \(b\).
\[\frac{a}{\sin A} = \frac{b}{\sin B}\]
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γ€° TRIG Β· Double Angle Identity
β˜…β˜… Medium β€” most common identity test question!
If \(\sin\theta = \dfrac{3}{5}\) and \(\theta\) is in Q1, find \(\sin(2\theta)\).
πŸ’‘ \(\sin(2\theta) = 2\sin\theta\cos\theta\) Β· First find \(\cos\theta\) using Pythagorean identity!
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γ€° TRIG Β· Law of Cosines
β˜…β˜… Medium β€” use when you have SAS or SSS!
In triangle \(ABC\): \(a=7,\; b=5,\; C=60Β°\). Find side \(c\).
\[c^2 = a^2 + b^2 - 2ab\cos C\]
πŸ”₯ Section 5 Β· Mixed Challenge
🌟 These questions connect multiple topics! Think carefully before picking.
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πŸ”₯ MIXED Β· Vector + Trig Connection
β˜…β˜… Medium β€” vector components use trig!
A force vector has magnitude \(10\) N at angle \(120Β°\) from the positive x-axis.
Express it as a component vector \(\langle F_x,\; F_y \rangle\).
πŸ’‘ \(F_x = |\vec{F}|\cos\theta,\quad F_y = |\vec{F}|\sin\theta\) β€” this IS the vector-trig bridge!
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πŸ”₯ MIXED Β· Polar + Trig + Complex Numbers
β˜…β˜…β˜… Hard β€” Boss level!
Write the complex number \(z = -1 + i\sqrt{3}\) in polar form \(r(\cos\theta + i\sin\theta)\).
⚠️ This combines: rectangularβ†’polar conversion AND trig values. Think quadrant II!