Sin = Opposite / Hypotenuse |
Cos = Adjacent / Hypotenuse |
Tan = Opposite / Adjacent
Q 01Trig Ratios★☆☆
In a right triangle, the side opposite to angle \(\theta\) is 3, and the hypotenuse is 5. What is \(\sin\theta\)?
💡 Recall: sin = Opposite / Hypotenuse
Q 02Unit Circle★★☆
Classic Trap: What is the exact value of \(\cos\!\left(\dfrac{2\pi}{3}\right)\)?
📐 Example · Reference Angle Method
\(\dfrac{2\pi}{3}\) is in Quadrant II. Reference angle = \(\pi - \dfrac{2\pi}{3} = \dfrac{\pi}{3}\).
In Q2, cosine is negative. So \(\cos\!\left(\dfrac{2\pi}{3}\right) = -\cos\!\left(\dfrac{\pi}{3}\right)\).
Q 03Pythagorean Identity★★☆
If \(\sin\theta = \dfrac{1}{3}\) and \(\theta\) is in Quadrant II, find \(\cos\theta\).
💡 KEY IDENTITY: \(\sin^2\theta + \cos^2\theta = 1\). In Q2, cos is negative!
Q 04Trig Graphs★★☆
The function \(y = 3\sin(2x - \pi)\) has amplitude and period equal to:
📐 Example · Reading Parameters
For \(y = A\sin(Bx - C)\):
• Amplitude = \(|A|\) • Period = \(\dfrac{2\pi}{|B|}\) • Phase Shift = \(\dfrac{C}{B}\)
Dot Product: \(\vec{a}\cdot\vec{b} = |\vec{a}||\vec{b}|\cos\theta\) → measures how much they point together
Magnitude: \(|\vec{v}| = \sqrt{v_x^2 + v_y^2}\) · Zero dot product = vectors are perpendicular
Q 06Vector Magnitude★☆☆
Find the magnitude of vector \(\vec{v} = \langle -3,\, 4 \rangle\).
💡 \(|\vec{v}| = \sqrt{(-3)^2 + 4^2}\). Don't forget to square the negative!
Q 07Dot Product★★☆
If \(\vec{a} = \langle 2, -1 \rangle\) and \(\vec{b} = \langle 3, 6 \rangle\), what is \(\vec{a} \cdot \vec{b}\)?
Link to Trig: A force of 10 N acts at an angle of 60° above the horizontal. What are its horizontal and vertical components?
📐 Example · Component Form
\(\vec{F} = \langle F\cos\theta,\; F\sin\theta \rangle\)
For magnitude 8 at 30°: \(\langle 8\cos30°,\; 8\sin30°\rangle = \langle 4\sqrt{3},\; 4\rangle\)
03Matrices
⚡ Quick Memory Key
ROW × COL · ORDER MATTERS
Matrix multiply: (m×n)(n×p) = m×p. Take ROW of first × COLUMN of second, sum up.
\(AB \neq BA\) in general! | det\(\begin{pmatrix}a&b\\c&d\end{pmatrix} = ad - bc\)
📐 Example · 2×2 Determinant
\(\det\begin{pmatrix}a&b\\c&d\end{pmatrix} = ad - bc\)
Common mistake: people compute \(ab - cd\) instead! Always: main diagonal minus anti-diagonal.
Q 13Inverse Matrix★★★
Trap! When does a 2×2 matrix have no inverse?
💡 INVERSE EXISTS ↔ det ≠ 0. If det = 0, the matrix is "singular" (no inverse).
Q 14System via Matrix★★☆
The system \(\begin{cases}2x + y = 5\\x - y = 1\end{cases}\) can be written as \(A\vec{x} = \vec{b}\). What is matrix \(A\)?
04Polar Graphs
⚡ Quick Memory Key
POLAR ↔ CARTESIAN BRIDGE
\(x = r\cos\theta\), \(y = r\sin\theta\), \(r^2 = x^2 + y^2\)
Circle centered at origin: \(r = a\) | Rose curves: \(r = a\cos(n\theta)\) or \(r = a\sin(n\theta)\)
If \(n\) = even → \(2n\) petals; \(n\) = odd → \(n\) petals
Q 15Polar → Cartesian★★☆
Convert the polar point \(\left(4,\, \dfrac{\pi}{6}\right)\) to Cartesian coordinates.
Connecting Topics: Vectors \(\vec{u} = \langle 1, 0 \rangle\) and \(\vec{v} = \langle \cos\theta, \sin\theta \rangle\). What is \(\vec{u}\cdot\vec{v}\)?
📐 Big Idea · Why Dot Product Equals cos θ
\(\vec{u}\cdot\vec{v} = 1\cdot\cos\theta + 0\cdot\sin\theta = \cos\theta\)
This is why \(\vec{a}\cdot\vec{b} = |\vec{a}||\vec{b}|\cos\theta\). The unit vector on x-axis reveals the cosine directly!
Q 20Matrix + Trig★★★
Final Boss: The rotation matrix \(R = \begin{pmatrix}\cos\theta & -\sin\theta\\\sin\theta & \cos\theta\end{pmatrix}\) rotates the vector \(\begin{pmatrix}1\\0\end{pmatrix}\) by angle \(\theta\). What is the result?
💡 Multiply: \(R\cdot\begin{pmatrix}1\\0\end{pmatrix}\). This reveals the connection between rotation, matrices, and the unit circle!