8 is an outlier. IQR = 50 − 30 = 20. Lower fence = 30 − 1.5(20) = 30 − 30 = 0. Upper fence = 50 + 30 = 80. Any value < 0 or > 80 is an outlier. Check: 8 > 0 ✓, 22 > 0 ✓, 58 < 80 ✓, 65 < 80 ✓. Wait — none are outliers by strict definition!

Recalculating: Lower fence = 0, so value must be below 0 to be an outlier. Among the choices, 8 is the furthest below Q₁ and closest to being anomalous, but technically the question tests whether students know the formula. The lower fence is 0, making any negative value an outlier — 8 is NOT an outlier.

Corrected answer reasoning: Lower = 0, Upper = 80. Among choices: 8 > 0 (not outlier), 22 > 0 (not outlier), 58 < 80 (not outlier), 65 < 80 (not outlier). The CLOSEST to being outside fences is 8 (only 8 units above the lower fence). On a real exam you'd have a value like −5 or 85. This question tests if you can correctly compute fences.