Self-Study Worksheet
Math Mastery
Algebra & Geometry
Core concepts, tricky questions, and memory anchors for confident problem-solving.
20 Questions
2 Units
Multiple Choice
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KEY: "has" → start value · "earns" → rate × variable · "wants" → goal
A \(45h + 8 = 93\)
B \(8h - 45 = 93\)
C \(8h + 45 = 93\)
D \(8 + 45h = 93\)
✗ Incorrect. Maya already has $45. Each hour earns $8, so after h hours she has 8h + 45.
Set that equal to 93: 8h + 45 = 93. Answer: C.
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TRANSLATE: "three times x decreased by 7" → 3x − 7 (NOT 7 − 3x)
A \(x = 4\)
B \(x = 9\)
C \(x = 13\)
D \(x = \frac{27}{3}\)
✗ Incorrect. Equation: \(3x - 7 = 20\). Add 7: \(3x = 27\). Divide by 3: \(x = 9\).
Note that D also equals 9, but B is the simplified correct answer. Answer: B.
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"at least" → ≥ · "at most" → ≤ · "more than" → > · "less than" → <
A \(42 + x > 48\)
B \(42 + x \geq 48\)
C \(x > 6\)
D \(42 - x \geq 48\)
✗ Incorrect. Leo needs his current height plus growth to meet OR exceed 48 in.
"At least" means ≥, so: \(42 + x \geq 48\). Option C is the solved form but misses the setup. Answer: B.
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OPPOSITE directions → ADD speeds: (rate₁ + rate₂) × time = total distance
A \(3 \text{ hours}\)
B \(5 \text{ hours}\)
C \(7.5 \text{ hours}\)
D \(2.5 \text{ hours}\)
✗ Incorrect. Combined speed = 60 + 40 = 100 mph. \(100t = 300\), so \(t = 3\) hours.
Common mistake: dividing 300 by only one speed. Answer: A.
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CONSECUTIVE EVEN: x, x+2, x+4 · CONSECUTIVE ODD: same pattern x, x+2, x+4
A \(24\)
B \(26\)
C \(28\)
D \(30\)
✗ Incorrect. Let integers be \(x, x+2, x+4\). Sum: \(3x + 6 = 78\), so \(3x = 72\), \(x = 24\).
The three integers are 24, 26, 28. Largest = 28. Answer: C.
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MIXTURE: (price₁)(qty₁) + (price₂)(qty₂) = (blended price)(total qty)
A \(5 \text{ lbs}\)
B \(8 \text{ lbs}\)
C \(10 \text{ lbs}\)
D \(12 \text{ lbs}\)
✗ Incorrect. Let \(x\) = lbs of Type A, then \(15-x\) = lbs of Type B.
\(4x + 7(15-x) = 5(15)\) → \(4x + 105 - 7x = 75\) → \(-3x = -30\) → \(x = 10\). Answer: C.
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y = mx + b · m = rate (per unit) · b = starting value (when x=0)
A \(C = 20t + 0.05\); b = 0.05
B \(C = 0.05t + 20\); b = 20, fixed fee
C \(C = 0.05t + 20\); b = 0.05, per-text cost
D \(C = 20t\); no y-intercept
✗ Incorrect. The equation is \(C = 0.05t + 20\). The y-intercept is 20, which is the
fixed monthly fee — the cost even with zero texts. Answer: B.
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"In n years" → add n to BOTH sides: (Emma+n) = 2(Jake+n)
A \(4 \text{ years old}\)
B \(6 \text{ years old}\)
C \(8 \text{ years old}\)
D \(12 \text{ years old}\)
✗ Incorrect. Now: \(E = 3J\). In 4 years: \(3J+4 = 2(J+4)\) → \(3J+4 = 2J+8\) → \(J=4\).
Jake is 4 years old now. Answer: A.
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UNIT RATE first: miles ÷ hours = mph → then multiply by new time
A \(200 \text{ miles}\)
B \(220 \text{ miles}\)
C \(240 \text{ miles}\)
D \(260 \text{ miles}\)
✗ Incorrect. Unit rate = \(\frac{150}{2.5} = 60\) mph. Distance in 4 hours = \(60 \times 4 = 240\) miles. Answer: C.
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−25% then +25% ≠ same price! Percentages apply to DIFFERENT bases
A \(\$80.00\)
B \(\$75.00\)
C \(\$82.50\)
D \(\$70.00\)
✗ Incorrect. Sale price: \(80 \times 0.75 = \$60\). Then +25%: \(60 \times 1.25 = \$75\).
The two 25%s act on different amounts! Answer: B.
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TRIANGLE SUM THEOREM: ∠A + ∠B + ∠C = 180° (always, no exceptions)
A \(37°\)
B \(43°\)
C \(47°\)
D \(52°\)
✗ Incorrect. \(55 + 78 + C = 180\) → \(133 + C = 180\) → \(C = 47°\). Answer: C.
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a² + b² = c² · Hypotenuse is ALWAYS c (the longest side, opposite right angle)
A \(11\)
B \(13\)
C \(15\)
D \(17\)
✗ Incorrect. \(5^2 + 12^2 = 25 + 144 = 169\). \(\sqrt{169} = 13\). This is the famous 5-12-13 triple! Answer: B.
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A = ½ × base × height · Think: triangle is HALF of a rectangle
A \(126 \text{ cm}^2\)
B \(63 \text{ cm}^2\)
C \(46 \text{ cm}^2\)
D \(94.5 \text{ cm}^2\)
✗ Incorrect. \(A = \frac{1}{2} \times 14 \times 9 = \frac{126}{2} = 63 \text{ cm}^2\).
Option A is the wrong answer students get by forgetting the ½. Answer: B.
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A = πr² · r = d ÷ 2 · ALWAYS halve diameter before squaring
A \(314 \text{ cm}^2\)
B \(31.4 \text{ cm}^2\)
C \(78.5 \text{ cm}^2\)
D \(157 \text{ cm}^2\)
✗ Incorrect. Radius = \(\frac{10}{2} = 5\) cm. \(A = 3.14 \times 5^2 = 3.14 \times 25 = 78.5 \text{ cm}^2\).
Option A uses diameter as radius — the classic mistake. Answer: C.
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S-U-pplementary = 1-8-0° · C-O-mplementary = 9-0° (C comes before S, 90 before 180)
A \(71°\)
B \(109°\)
C \(64°\)
D \(116°\)
✗ Incorrect. Let \(Y = y\), then \(X = y + 38\). Supplementary: \(y + (y+38) = 180\) → \(2y = 142\) → \(y = 71°\).
So \(X = 71 + 38 = 109°\). Answer: B.
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V = l × w × h · then multiply by percent as decimal: 80% → × 0.80
A \(24{,}000 \text{ cm}^3\)
B \(30{,}000 \text{ cm}^3\)
C \(25{,}000 \text{ cm}^3\)
D \(27{,}500 \text{ cm}^3\)
✗ Incorrect. Full volume = \(40 \times 25 \times 30 = 30{,}000 \text{ cm}^3\).
80% full: \(30{,}000 \times 0.8 = 24{,}000 \text{ cm}^3\). Answer: A.
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Alternate angles = EQUAL · Co-interior angles = SUPPLEMENTARY (add to 180°)
A \(65°\)
B \(90°\)
C \(115°\)
D \(125°\)
✗ Incorrect. Co-interior (same-side interior) angles are supplementary: \(65 + x = 180\) → \(x = 115°\).
Students often confuse this with alternate angles (which are equal). Answer: C.
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COMPOSITE PERIMETER: trace ONLY outside edges · cut adds edges, doesn't remove outer ones
A \(28 \text{ units}\)
B \(30 \text{ units}\)
C \(34 \text{ units}\)
D \(38 \text{ units}\)
✗ Incorrect. Original rectangle perimeter = \(2(7+8)=30\). Removing a corner 3×4 piece:
two sides disappear (3 and 4) but two new sides appear (3 and 4). Net change = 0. Perimeter = 30 units. Answer: B.
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SIMILAR: all sides share same RATIO (scale factor) · find k first: k = new/old
A \(12\)
B \(13\)
C \(15\)
D \(18\)
✗ Incorrect. Scale factor: \(k = \frac{9}{6} = 1.5\). Apply to longest side: \(10 \times 1.5 = 15\). Answer: C.
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EXTERIOR ANGLE = sum of the TWO non-adjacent interior angles (shortcut!)
A \(71°\)
B \(109°\)
C \(118°\)
D \(131°\)
✗ Incorrect. Exterior Angle Theorem: exterior angle = 42 + 67 = 109°.
(Alternatively: interior angle = 180 − 42 − 67 = 71°, exterior = 180 − 71 = 109°.) Answer: B.