Trigonometry · Complete Study Guide

sin · cos · tan

From the unit circle to exam-level problems — master every concept with instant feedback.

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The Golden Mnemonic

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The master key
SOH · CAH · TOA
SOH — Sine = Opposite / Hypotenuse  ·  CAH — Cosine = Adjacent / Hypotenuse  ·  TOA — Tangent = Opposite / Adjacent
sin θ
⚡ "SINE = OPPOSITE SIDE"
\( \sin\theta = \dfrac{\text{Opposite}}{\text{Hypotenuse}} \)
\( \sin\theta = \dfrac{y}{r} \) on unit circle
sin 0° = 0 sin 30° = ½ sin 45° = √2/2 sin 60° = √3/2 sin 90° = 1
cos θ
⚡ "COSINE = CLOSE (ADJACENT)"
\( \cos\theta = \dfrac{\text{Adjacent}}{\text{Hypotenuse}} \)
\( \cos\theta = \dfrac{x}{r} \) on unit circle
cos 0° = 1 cos 30° = √3/2 cos 45° = √2/2 cos 60° = ½ cos 90° = 0
tan θ
⚡ "TAN = TOP over ADJACENT"
\( \tan\theta = \dfrac{\text{Opposite}}{\text{Adjacent}} = \dfrac{\sin\theta}{\cos\theta} \)
\( \tan\theta = \dfrac{y}{x} \) on unit circle
tan 0° = 0 tan 30° = 1/√3 tan 45° = 1 tan 60° = √3 tan 90° = ∞
Key Angle Values

The 5 angles you must know cold.

DegreesRadianssin θcos θtan θ
\(0\)\(0\)\(1\)\(0\)
30°\(\frac{\pi}{6}\)\(\frac{1}{2}\)\(\frac{\sqrt{3}}{2}\)\(\frac{1}{\sqrt{3}}\)
45°\(\frac{\pi}{4}\)\(\frac{\sqrt{2}}{2}\)\(\frac{\sqrt{2}}{2}\)\(1\)
60°\(\frac{\pi}{3}\)\(\frac{\sqrt{3}}{2}\)\(\frac{1}{2}\)\(\sqrt{3}\)
90°\(\frac{\pi}{2}\)\(1\)\(0\)undefined
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20 Questions

Arranged from fundamental to exam-level. Each question gives immediate feedback with full explanation.

● Easy — Q1–7 ● Medium — Q8–14 ● Hard — Q15–20
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