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Algebra II · Advanced Geometry

Master the
Hard Ones

20 questions built around the concepts students miss most often at the Algebra II / Geometry level.

Algebra II — 10 Questions
Q 01 Algebra II Medium Complex Numbers
🔑KEY: i² = −1 always. Simplify powers of i cyclically: i¹=i, i²=−1, i³=−i, i⁴=1, then repeat.
What is the value of \( i^{14} \)?
Cycle trick Divide the exponent by 4 and look at the remainder.
\( 14 \div 4 = 3 \) remainder 2 → same as \( i^2 \) → \( = ? \)
A \( i \)
B \( -1 \)
C \( 1 \)
D \( -i \)
Q 02 Algebra II Tricky Logarithms
🔑KEY: log_b(x) = y ↔ b^y = x — "log asks: what exponent?"
Solve for \( x \): \(\quad \log_3(x) = 4\)
Convert log → exponential \( \log_3(x) = 4 \) means \( 3^4 = x \)
Think: base 3, raised to power 4 = ?
A \( x = 12 \)
B \( x = 7 \)
C \( x = 81 \)
D \( x = 64 \)
Q 03 Algebra II Tricky Quadratic Formula
🔑KEY: discriminant = b²−4ac. If >0: two real roots, =0: one root, <0: no real roots (complex)
How many real solutions does \( 2x^2 - 4x + 5 = 0 \) have?
Check the discriminant only — don't solve! \( a=2,\ b=-4,\ c=5 \)
\( b^2 - 4ac = (-4)^2 - 4(2)(5) = 16 - 40 = -24 \)
Negative discriminant → ?
A Two distinct real solutions
B Exactly one real solution
C No real solutions
D Infinitely many solutions
Q 04 Algebra II Medium Exponential Functions
🔑KEY: growth: b>1 | decay: 0<b<1 in y = a·bˣ
The function \( f(x) = 500 \cdot (0.8)^x \) models exponential ___.
Identify the base Base = 0.8 → Is it greater than 1 or less than 1?
Less than 1 → the value gets smaller each step → growth or decay?
A Growth, because 500 is large
B Decay, because the base 0.8 is less than 1
C Growth, because the exponent x is positive
D Neither — it is linear
Q 05 Algebra II Tricky Rational Expressions
🔑KEY: excluded values — set the denominator = 0 and solve; those x-values are EXCLUDED
For the expression \(\dfrac{x+3}{x^2 - 9}\), which values of \( x \) are excluded?
Factor the denominator first \( x^2 - 9 = (x-3)(x+3) \)
Set each factor = 0: \( x = 3 \) and \( x = -3 \)
Both are excluded — even though \( x+3 \) also cancels!
A Only \( x = 3 \)
B Only \( x = -3 \)
C \( x = 3 \) and \( x = -3 \)
D No excluded values
Q 06 Algebra II Medium Inverse Functions
🔑KEY: swap x and y, then solve for y — that's the inverse!
Find the inverse of \( f(x) = 3x - 6 \).
Steps Step 1: Write \( y = 3x - 6 \)
Step 2: Swap x and y → \( x = 3y - 6 \)
Step 3: Solve for y → \( y = \dfrac{x+6}{3} \)
A \( f^{-1}(x) = \dfrac{x-6}{3} \)
B \( f^{-1}(x) = \dfrac{x+6}{3} \)
C \( f^{-1}(x) = 3x + 6 \)
D \( f^{-1}(x) = \dfrac{1}{3x-6} \)
Q 07 Algebra II Tricky Sequences — Arithmetic vs Geometric
🔑KEY: Arithmetic = ADD constant (common difference d) | Geometric = MULTIPLY constant (common ratio r)
Which sequence is geometric?
Test: divide consecutive terms Geometric → each term ÷ previous term = SAME ratio
Arithmetic → each term − previous term = SAME difference
A \( 3,\ 7,\ 11,\ 15,\ \ldots \)
B \( 2,\ 5,\ 8,\ 11,\ \ldots \)
C \( 4,\ 12,\ 36,\ 108,\ \ldots \)
D \( 1,\ 4,\ 9,\ 16,\ \ldots \)
Q 08 Algebra II Medium Polynomial — End Behavior
🔑KEY: leading term decides end behavior — check degree (even/odd) and leading coefficient (+ / −)
Describe the end behavior of \( f(x) = -3x^4 + 2x - 1 \) as \( x \to +\infty \).
Two-step check Leading term: \( -3x^4 \)
Even degree + negative leading coeff → both ends go DOWN
As \( x \to +\infty \), \( f(x) \to \) ?
A \( f(x) \to +\infty \)
B \( f(x) \to -\infty \)
C \( f(x) \to 0 \)
D \( f(x) \to +\infty \) on left, \( -\infty \) on right
Q 09 Algebra II Tricky Radical Equations
🔑KEY: after solving, always CHECK for extraneous solutions by plugging back in!
Solve: \(\sqrt{2x + 3} = x - 1\). Which value(s) of \( x \) are valid solutions?
Solve & Check Square both sides: \( 2x+3 = (x-1)^2 = x^2-2x+1 \)
→ \( x^2 - 4x - 2 = 0 \)... wait, let's try: rearrange → \(x^2 -4x -2=0\). Actually check \(x=6\) and \(x=-1\): plug back into original to see which works!
A \( x = -1 \) only
B \( x = 6 \) only
C \( x = 6 \) and \( x = -1 \)
D No solution
Q 10 Algebra II Medium Vertex Form of Parabola
🔑KEY: vertex form: y = a(x − h)² + k → vertex is (h, k). Watch the SIGN of h!
What is the vertex of \( f(x) = 2(x + 4)^2 - 7 \)?
Trap: sign of h! Form is \( a(x - h)^2 + k \), so \( (x+4) = (x-(-4)) \)
→ \( h = -4 \), \( k = -7 \) → vertex = ?
Common mistake: writing (+4, −7) instead of (−4, −7)
A \( (4,\ -7) \)
B \( (4,\ 7) \)
C \( (-4,\ -7) \)
D \( (-4,\ 7) \)
Advanced Geometry — 10 Questions
Q 11 Geometry Medium Circle — Arc Length
🔑KEY: Arc Length = (central angle / 360) × 2πr — it's a FRACTION of the full circumference
A circle has radius \( 9 \). What is the arc length for a central angle of \( 80° \)?
(Leave answer in terms of \( \pi \))
Formula Arc Length \( = \dfrac{80}{360} \times 2\pi(9) = \dfrac{2}{9} \times 18\pi = ? \)
A \( 2\pi \)
B \( 4\pi \)
C \( 8\pi \)
D \( 9\pi \)
Q 12 Geometry Tricky Triangle Similarity — Scale Factor
🔑KEY: similar triangles → sides are PROPORTIONAL — set up ratios of corresponding sides
Triangles \( ABC \sim PQR \). Side \( AB = 6 \), \( BC = 9 \), and \( PQ = 4 \). Find \( QR \).
Proportion setup \( \dfrac{AB}{PQ} = \dfrac{BC}{QR} \) → \( \dfrac{6}{4} = \dfrac{9}{QR} \)
Cross-multiply: \( 6 \cdot QR = 36 \) → \( QR = ? \)
A \( QR = 5 \)
B \( QR = 5.5 \)
C \( QR = 6 \)
D \( QR = 8 \)
Q 13 Geometry Tricky Circle Theorems — Inscribed Angle
🔑KEY: Inscribed angle = ½ × intercepted arc | Central angle = intercepted arc (full, not half)
An inscribed angle in a circle intercepts an arc of \( 140° \). What is the inscribed angle?
Inscribed Angle Theorem Inscribed angle = \( \dfrac{1}{2} \times \text{arc} = \dfrac{1}{2} \times 140° = ? \)
Don't confuse with the central angle (which equals the arc directly)
A \( 140° \)
B \( 70° \)
C \( 280° \)
D \( 35° \)
Q 14 Geometry Medium Volume — Cone
🔑KEY: V(cone) = ⅓πr²h — one-third of a cylinder! Don't forget the ⅓.
A cone has radius \( 6 \) cm and height \( 10 \) cm. Find its volume. (Use \( \pi \approx 3.14 \))
Formula \( V = \dfrac{1}{3}\pi r^2 h = \dfrac{1}{3}(3.14)(6^2)(10) \)
\( = \dfrac{1}{3}(3.14)(36)(10) = \dfrac{1}{3}(1130.4) = ? \)
A \( 1130.4 \text{ cm}^3 \)
B \( 376.8 \text{ cm}^3 \)
C \( 188.4 \text{ cm}^3 \)
D \( 565.2 \text{ cm}^3 \)
Q 15 Geometry Tricky Coordinate Geometry — Distance
🔑KEY: Distance = √[(x₂−x₁)² + (y₂−y₁)²] — Pythagorean theorem in disguise!
Find the distance between \( A(-3,\ 2) \) and \( B(5,\ -4) \).
Plug in carefully \( d = \sqrt{(5-(-3))^2 + (-4-2)^2} = \sqrt{8^2 + (-6)^2} = \sqrt{64 + 36} = \sqrt{100} = ? \)
A \( d = 8 \)
B \( d = 14 \)
C \( d = 10 \)
D \( d = \sqrt{28} \)
Q 16 Geometry Medium Trigonometry — SOH CAH TOA
🔑KEY: SOH: sin=opp/hyp | CAH: cos=adj/hyp | TOA: tan=opp/adj
In a right triangle, the angle \( \theta = 30° \), and the hypotenuse \( = 20 \). Find the side opposite \( \theta \).
Which ratio? Opposite + Hypotenuse → use sine
\( \sin(30°) = \dfrac{\text{opp}}{\text{hyp}} \) → \( 0.5 = \dfrac{\text{opp}}{20} \) → opp = ?
Recall: \( \sin(30°) = 0.5 \)
A \( 5 \)
B \( 40 \)
C \( 10 \)
D \( 10\sqrt{3} \)
Q 17 Geometry Tricky Surface Area — Sphere
🔑KEY: SA(sphere) = 4πr² | V(sphere) = (4/3)πr³ — don't mix them up!
A sphere has a radius of \( 5 \) cm. What is its surface area? (Use \( \pi \approx 3.14 \))
Formula SA = \( 4\pi r^2 = 4(3.14)(5^2) = 4(3.14)(25) = ? \)
Trap: Students often use \( 2\pi r^2 \) (that's a hemisphere!) or confuse with volume formula.
A \( 78.5 \text{ cm}^2 \)
B \( 157 \text{ cm}^2 \)
C \( 314 \text{ cm}^2 \)
D \( 523.3 \text{ cm}^2 \)
Q 18 Geometry Tricky Parallel Lines — Slope Condition
🔑KEY: Parallel → same slope | Perpendicular → slopes are negative reciprocals (product = −1)
Line \( \ell \) has slope \( \dfrac{3}{4} \). What is the slope of a line perpendicular to \( \ell \)?
Negative reciprocal rule Flip the fraction AND change the sign:
\( \dfrac{3}{4} \) → flip to \( \dfrac{4}{3} \) → change sign → \( -\dfrac{4}{3} \)
Check: \( \dfrac{3}{4} \times (-\dfrac{4}{3}) = -1 \) ✓
A \( \dfrac{3}{4} \)
B \( \dfrac{4}{3} \)
C \( -\dfrac{4}{3} \)
D \( -\dfrac{3}{4} \)
Q 19 Geometry Medium Dilation — Scale Factor
🔑KEY: Dilation multiplies ALL coordinates by scale factor k — (x, y) → (kx, ky)
Point \( P(4,\ -6) \) is dilated by a scale factor of \( \dfrac{1}{2} \) from the origin. What are the new coordinates?
Multiply each coordinate \( x' = \dfrac{1}{2}(4) = 2 \)
\( y' = \dfrac{1}{2}(-6) = -3 \)
New point = ( ?, ? )
A \( (8,\ -12) \)
B \( (2,\ -3) \)
C \( (4,\ -3) \)
D \( (2,\ -6) \)
Q 20 Geometry Tricky Geometric Proof — Congruence (CPCTC)
🔑KEY: CPCTC = Corresponding Parts of Congruent Triangles are Congruent — used AFTER proving triangles ≅
In a proof, you've shown that \( \triangle ABD \cong \triangle CBD \). To conclude that \( \angle A \cong \angle C \), you use ___.
Order matters in proofs Step 1: Prove the triangles are congruent (SAS, ASA, SSS, AAS…)
Step 2: THEN use CPCTC to say any matching parts are equal
You CANNOT use CPCTC as a reason to prove congruence — only after!
A SAS (Side-Angle-Side)
B Definition of congruent triangles
C CPCTC
D Reflexive Property

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