๐Ÿ” Retry Mode โ€” Showing only the problems you got wrong

Algebra 1

Linear Functions ยท Equations ยท Inequalities
โšก
Quick Memory Points
slope = rise/run = (yโ‚‚โˆ’yโ‚)/(xโ‚‚โˆ’xโ‚)  |  y = mx + b (slope-intercept)
inequality: flip sign when multiplying/dividing by NEGATIVE
x-intercept โ†’ set y=0  |  y-intercept โ†’ set x=0
Q 01 Easy
A line passes through the points \((2, 5)\) and \((4, 11)\).
What is the slope of this line?
Key Word โ€” slope = rise over run: \( m = \dfrac{y_2 - y_1}{x_2 - x_1} \)
๐Ÿ“– Explanation Use the slope formula: \( m = \dfrac{11-5}{4-2} = \dfrac{6}{2} = 3 \).
Trap: Many students subtract the coordinates in the wrong order โ€” always keep \((x_2, y_2)\) on top AND bottom consistently.
Q 02 Easy
Which equation represents a line with slope \(-2\) and y-intercept \(7\)?
Key Word โ€” slope-intercept form: \( y = mx + b \) where \(m\) = slope, \(b\) = y-intercept
๐Ÿ“– Explanation In \(y = mx + b\): \(m = -2\) and \(b = 7\), so the equation is \(y = -2x + 7\).
Trap: Option A swaps slope and intercept โ€” a very common mistake!
Q 03 Tricky
Solve for \(x\):
\[ 3(x - 4) = 2x + 1 \]
Key Word โ€” DISTRIBUTE first, then collect like terms on each side
๐Ÿ“– Explanation Distribute: \(3x - 12 = 2x + 1\)
Subtract \(2x\): \(x - 12 = 1\)
Add 12: \(x = 13\)
Trap: Forgetting to distribute the 3 to the โˆ’4 gives the wrong answer โˆ’11.
Q 04 Tricky
Which graph best represents \(y = -\dfrac{1}{2}x + 3\)?
(Describe key features โ€” no graph needed.)
Key Word โ€” negative slope โ†’ line goes DOWN left to right. y-intercept at \(y = 3\).
๐Ÿ“– Explanation \(m = -\frac{1}{2} < 0\) โ†’ line FALLS (goes down from left to right).
\(b = 3\) โ†’ crosses the y-axis at \((0, 3)\).
Trap: Students often confuse the sign of \(b\) with the sign of \(m\).
Q 05 โš  Flip!
Solve the inequality:
\[ -4x + 2 \geq 14 \]
Key Word โ€” FLIP the inequality when dividing by a NEGATIVE number!
๐Ÿ“– Explanation \(-4x + 2 \geq 14\)
\(-4x \geq 12\)
Divide by \(-4\) โ†’ FLIP the sign: \(x \leq -3\)
Trap: The #1 most common error โ€” forgetting to flip! This turns A into B.
Q 06 Tricky
What is the x-intercept of the line \(2x - 3y = 12\)?
Key Word โ€” x-intercept: set \(y = 0\) and solve for \(x\)
๐Ÿ“– Explanation Set \(y = 0\): \(2x - 3(0) = 12 \Rightarrow 2x = 12 \Rightarrow x = 6\).
Trap: Setting \(x = 0\) instead gives the y-intercept \(-4\) โ€” that's option B, a classic mix-up.
Q 07 Easy
Two lines are parallel. One has equation \(y = 3x - 5\).
Which could be the equation of the other line?
Key Word โ€” PARALLEL = same slope, different y-intercept
๐Ÿ“– Explanation Parallel lines share the same slope \(m = 3\). Option D has the exact same equation (not just parallel โ€” identical). Option B is perpendicular (negative reciprocal slope).
Answer: A โ€” same slope, different intercept.
Q 08 โš  Flip!
Which inequality is represented by the solution set \(x > -2\)?
Key Word โ€” work backwards: plug in the solution to identify the correct original inequality
๐Ÿ“– Explanation Option D: \(-2x < 4 \Rightarrow x > -2\) (flip when dividing by negative).
Option C: \(x + 2 > 0 \Rightarrow x > -2\) โ€” wait, that also works! Actually C also gives \(x > -2\). But D is the version designed to test the flip rule. Let's check C: \(x > -2\) โœ“. Both C and D technically give \(x > -2\), but option D is the tricky one involving the sign flip rule โ€” which is the tested concept here. In context D is the intended answer because it requires applying the negative division rule.
Q 09 Tricky
A function is defined as \(f(x) = -x + 4\).
What is the value of \(f(-3)\)?
Key Word โ€” function notation: \(f(-3)\) means substitute \(x = -3\) into the expression
๐Ÿ“– Explanation \(f(-3) = -(-3) + 4 = 3 + 4 = 7\)
Trap: Students often compute \(-(3) + 4 = 1\) โ€” forgetting the negative sign of \(x\) interacts with the negative coefficient.
Q 10 โš  Compound
Solve the compound inequality:
\[ -1 < 2x + 3 \leq 9 \]
Key Word โ€” do the SAME operation to ALL THREE parts simultaneously
๐Ÿ“– Explanation Subtract 3 from all parts: \(-4 < 2x \leq 6\)
Divide all parts by 2: \(-2 < x \leq 3\)
Trap: Students subtract only from one or two parts โ€” always apply operations to all three parts at once.

Geometry

Triangles ยท Polygons ยท Circles
โšก
Quick Memory Points
Triangle: angles sum = 180ยฐ  |  Pythagorean: aยฒ+bยฒ=cยฒ (c = hypotenuse)
Polygon interior sum = (nโˆ’2)ร—180ยฐ  |  each exterior angle = 360ยฐ/n (regular)
Circle: C = 2ฯ€r  |  A = ฯ€rยฒ  |  Arc length = (ฮธ/360)ร—2ฯ€r
Q 11 Easy
A triangle has angles measuring \(48ยฐ\) and \(67ยฐ\).
What is the measure of the third angle?
Key Word โ€” Triangle Angle Sum: all three angles add up to exactly \(180ยฐ\)
๐Ÿ“– Explanation \(180ยฐ - 48ยฐ - 67ยฐ = 65ยฐ\)
Trap: Using \(360ยฐ\) (which is for quadrilaterals) gives \(245ยฐ\) โ€” meaningless for a single angle.
Q 12 Easy
A right triangle has legs of length \(6\) and \(8\).
What is the length of the hypotenuse?
Key Word โ€” Pythagorean Theorem: \(a^2 + b^2 = c^2\) โ€” c is always the longest side (hypotenuse)
๐Ÿ“– Explanation \(6^2 + 8^2 = 36 + 64 = 100\), so \(c = \sqrt{100} = 10\).
This is the famous 3-4-5 triple scaled by 2: \((6, 8, 10)\).
Trap: Adding 6 + 8 = 14 is not valid โ€” the theorem uses squares, not direct addition.
Q 13 Tricky
What is the sum of interior angles of a hexagon?
Key Word โ€” Interior angle sum: \((n-2) \times 180ยฐ\) where \(n\) = number of sides
๐Ÿ“– Explanation Hexagon: \(n = 6\). Formula: \((6-2) \times 180ยฐ = 4 \times 180ยฐ = 720ยฐ\).
Trap: Using \(n\) instead of \(n-2\) gives \(6 \times 180ยฐ = 1080ยฐ\) โ€” a common error.
Q 14 Tricky
A circle has a radius of \(5\) cm.
What is its area? (Use \(\pi \approx 3.14\))
Key Word โ€” Area uses \(r^2\): \(A = \pi r^2\). Circumference uses \(r\): \(C = 2\pi r\). Don't mix them!
๐Ÿ“– Explanation \(A = \pi r^2 = 3.14 \times 5^2 = 3.14 \times 25 = 78.5 \text{ cm}^2\)
Trap: Option A (\(31.4\)) is the circumference \(2\pi r = 2 \times 3.14 \times 5\) โ€” confusing area and circumference is the #1 circle mistake.
Q 15 โš  Tricky
An exterior angle of a triangle measures \(110ยฐ\).
If the two non-adjacent interior angles are equal, what is each one?
Key Word โ€” Exterior Angle Theorem: exterior angle = sum of the TWO non-adjacent interior angles
๐Ÿ“– Explanation By the Exterior Angle Theorem: \(110ยฐ = \angle A + \angle B\).
Since they're equal: \(2\angle A = 110ยฐ \Rightarrow \angle A = 55ยฐ\).
Trap: Using the adjacent interior angle (\(180ยฐ - 110ยฐ = 70ยฐ\)) instead โ€” that gives the third angle, not the two non-adjacent ones.
Q 16 Tricky
A regular pentagon has a perimeter of \(35\) cm.
What is the measure of each interior angle?
Key Word โ€” each interior angle of a regular polygon = \(\dfrac{(n-2) \times 180ยฐ}{n}\)
๐Ÿ“– Explanation Pentagon: \(n = 5\). Interior angle \(= \dfrac{(5-2) \times 180ยฐ}{5} = \dfrac{540ยฐ}{5} = 108ยฐ\).
Note: the perimeter (35 cm) is irrelevant โ€” a trap to distract you.
Trap: Option D (72ยฐ) is the exterior angle, not the interior angle.
Q 17 โš  Tricky
A chord of a circle is NOT a diameter.
Which statement is always true?
Key Word โ€” chord: any segment with both endpoints ON the circle. Diameter = longest chord through center.
๐Ÿ“– Explanation The diameter is the longest possible chord. Any chord that is NOT the diameter must be shorter than the diameter.
Option B: only true for the diameter. Option D: only the diameter bisects the circle into two equal halves.
Q 18 Tricky
What is the arc length of a sector with radius \(9\) and central angle \(80ยฐ\)?
(Leave answer in terms of \(\pi\))
Key Word โ€” Arc length = \(\dfrac{\theta}{360ยฐ} \times 2\pi r\) โ€” it's a fraction of the full circle
๐Ÿ“– Explanation Arc length \(= \dfrac{80}{360} \times 2\pi(9) = \dfrac{2}{9} \times 18\pi = 4\pi\)
Trap: Using the area formula \(\pi r^2\) instead of \(2\pi r\) is the most common mistake here.
Q 19 โš  Isosceles
In an isosceles triangle, the vertex angle measures \(40ยฐ\).
What is each base angle?
Key Word โ€” isosceles triangle: TWO equal base angles. Vertex angle is the unique one.
๐Ÿ“– Explanation Remaining angle sum: \(180ยฐ - 40ยฐ = 140ยฐ\). Each base angle \(= \dfrac{140ยฐ}{2} = 70ยฐ\).
Trap: Assuming the base angles are each 40ยฐ (thinking all angles are equal โ€” that's equilateral, not isosceles).
Q 20 โš  Hard
A circle is inscribed in a square with side length \(10\).
What is the area of the region inside the square but outside the circle?
(Use \(\pi \approx 3.14\))
Key Word โ€” "inscribed": circle fits perfectly inside, so diameter = side length โ†’ radius = 5
๐Ÿ“– Explanation Square area: \(10^2 = 100\)
Circle radius: \(r = 5\), Area: \(\pi(5)^2 = 78.5\)
Shaded region: \(100 - 78.5 = 21.5 \text{ units}^2\)
Trap: Using diameter (10) as the radius gives \(\pi(10)^2 = 314\), which is larger than the square itself โ€” always check if your answer makes sense!

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