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Convert 150° to radians:
150 × (π/180) = 150π/180 = 5π/6
Find sin(5π/6). 5π/6 is in QII; reference angle = π − 5π/6 = π/6. In QII sine is positive.
sin(5π/6) = sin(π/6) = 1/2
Right triangle: opp = 3, adj = 4, hyp = 5 (verify: 3²+4²=25=5² ✓)
sin θ = 3/5 | cos θ = 4/5 | tan θ = 3/4 | sec θ = 5/4
y = 3 sin(2x − π) + 1
A=3 → amplitude = 3 | B=2 → period = π
Phase shift = π/2 right | Vertical shift = 1 up
cos(75°) = cos(45° + 30°)
= cos45° cos30° − sin45° sin30°
= (√2/2)(√3/2) − (√2/2)(1/2) = (√6 − √2)/4
arctan(√3) = ? Find θ in (−π/2, π/2) where tan θ = √3.
tan(π/3) = √3 → arctan(√3) = π/3
a = 5, b = 7, C = 60°. Find c:
c² = 25 + 49 − 2(5)(7)(0.5) = 74 − 35 = 39
c = √39 ≈ 6.24
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